The figure, not drawn to scale, shows a rectangle, ABCD, which is divided in 4 parts, E, F, G, and H. The ratio of the area of H to the area of G is 2 : 5. The ratio of the area of G to the area of F is 7 : 9. If the area of E is 528 cm
2, what is the area of the rectangle ABCD?
| H |
G |
F |
E |
| 2x7 |
5x7 |
|
|
| |
7x5 |
9x5 |
|
| 14 u |
35 u |
45 u |
24 u |
Area G is the repeated identity.
LCM of 5 and 7 = 35
Half of the area of the rectangle
= Area H + Area F
= 14 u + 45 u
= 59 u
Area of E
= Half of the area of the rectangle - Area G
= 59 u - 35 u
= 24 u
24 u = 528
1 u = 528 ÷ 24 = 22
Area of the rectangle
= 59 u x 2
= 118 u
= 118 x 22
= 2596 cm
2 Answer(s): 2596 cm
2 
