The figure is made up of two squares and a triangle. The ratio of the area of Triangle T to that of Square V is 11 : 1. The ratio of the shaded area to that of the unshaded area is 1 : 3. If the difference between areas of Triangle T and Square U is 522 cm
2, what is the area of Square V?
Area of Triangle T |
Area of Square V |
Shaded area |
Unshaded area |
Total area |
11x4 |
1x4 |
|
|
11x4 |
|
|
1x11 |
3x11 |
4x11 |
44 u |
4 u |
11 u |
33 u |
44 u |
Area of Triangle T = Total area of the figure
Total area is the unchanged total. Make the total area the same.
LCM of 11 and 4 = 44
Area of Square U
= 11 u + 4 u
= 15 u
Difference between the areas of Triangle T and Square U
= 44 u - 15 u
= 29 u
29 u = 522
1 u = 522 ÷ 29 = 18
Area of Square V
= 4 u
= 4 x 18
= 72 cm
2 Answer(s): 72 cm
2