The figure is made up of two squares and a triangle. The ratio of the area of Triangle N to that of Square Q is 13 : 1. The ratio of the shaded area to that of the unshaded area is 1 : 3. If the difference between areas of Triangle N and Square P is 595 cm
2, what is the area of Square Q?
Area of Triangle N |
Area of Square Q |
Shaded area |
Unshaded area |
Total area |
13x4 |
1x4 |
|
|
13x4 |
|
|
1x13 |
3x13 |
4x13 |
52 u |
4 u |
13 u |
39 u |
52 u |
Area of Triangle N = Total area of the figure
Total area is the unchanged total. Make the total area the same.
LCM of 13 and 4 = 52
Area of Square P
= 13 u + 4 u
= 17 u
Difference between the areas of Triangle N and Square P
= 52 u - 17 u
= 35 u
35 u = 595
1 u = 595 ÷ 35 = 17
Area of Square Q
= 4 u
= 4 x 17
= 68 cm
2 Answer(s): 68 cm
2