The figure, not drawn to scale, is made up of 3 different triangles D, E and F. 25% of triangle D and 30% of triangle F is shaded. The shaded area of D is the same as the shaded area of F. What fraction of the figure is shaded if 20% of Triangle E is shaded?
Unshaded area of D |
Shaded area of D |
Unshaded area of F |
Shaded area of F |
3x3 |
1x3 |
7x1 |
3x1 |
9 u |
3 u |
7 u |
3 u |
25% =
25100 =
14 30% =
30100 =
310 20% =
20100 =
15The shaded area of D is the same as the shaded area of F.
Make the LCM of the shaded area of D and shaded area of F the same.
LCM of 1 and 3 = 3
15 of E is shaded
= Shaded area of D + Shaded area of F
= 3 u + 3 u
= 6 u
Fraction of E that is unshaded
= 1 -
15 =
45 15 of E = 6 u
45 of E = 4 x 6 u = 24 u
Fraction of the figure that is shaded if 20% of Triangle E is shaded
=
6 + 69 + 24 + 7 + 6 + 6 =
1252=
313 Answer(s):
313