The figure, not drawn to scale, is made up of 3 different triangles L, M and N. 20% of triangle L and 30% of triangle N is shaded. The shaded area of L is the same as the shaded area of N. What fraction of the figure is shaded if 25% of Triangle M is shaded?
Unshaded area of L |
Shaded area of L |
Unshaded area of N |
Shaded area of N |
4x3 |
1x3 |
7x1 |
3x1 |
12 u |
3 u |
7 u |
3 u |
20% =
20100 =
15 30% =
30100 =
310 25% =
25100 =
14The shaded area of L is the same as the shaded area of N.
Make the LCM of the shaded area of L and shaded area of N the same.
LCM of 1 and 3 = 3
14 of M is shaded
= Shaded area of L + Shaded area of N
= 3 u + 3 u
= 6 u
Fraction of M that is unshaded
= 1 -
14 =
34 14 of M = 6 u
34 of M = 3 x 6 u = 18 u
Fraction of the figure that is shaded if 25% of Triangle M is shaded
=
6 + 612 + 18 + 7 + 6 + 6=
1249 Answer(s):
1249