The figure, not drawn to scale, is made up of 3 different triangles B, C and D. 20% of triangle B and 30% of triangle D is shaded. The shaded area of B is the same as the shaded area of D. What fraction of the figure is shaded if 25% of Triangle C is shaded?
Unshaded area of B |
Shaded area of B |
Unshaded area of D |
Shaded area of D |
4x3 |
1x3 |
7x1 |
3x1 |
12 u |
3 u |
7 u |
3 u |
20% =
20100 =
15 30% =
30100 =
310 25% =
25100 =
14The shaded area of B is the same as the shaded area of D.
Make the LCM of the shaded area of B and shaded area of D the same.
LCM of 1 and 3 = 3
14 of C is shaded
= Shaded area of B + Shaded area of D
= 3 u + 3 u
= 6 u
Fraction of C that is unshaded
= 1 -
14 =
34 14 of C = 6 u
34 of C = 3 x 6 u = 18 u
Fraction of the figure that is shaded if 25% of Triangle C is shaded
=
6 + 612 + 18 + 7 + 6 + 6=
1249 Answer(s):
1249