The figure, not drawn to scale, is made up of 3 different triangles M, N and P. 15% of triangle M and 25% of triangle P is shaded. The shaded area of M is the same as the shaded area of P. What fraction of the figure is shaded if 20% of Triangle N is shaded?
Unshaded area of M |
Shaded area of M |
Unshaded area of P |
Shaded area of P |
17x1 |
3x1 |
3x3 |
1x3 |
17 u |
3 u |
9 u |
3 u |
15% =
15100 =
320 25% =
25100 =
14 20% =
20100 =
15The shaded area of M is the same as the shaded area of P.
Make the LCM of the shaded area of M and shaded area of P the same.
LCM of 3 and 1 = 3
15 of N is shaded
= Shaded area of M + Shaded area of P
= 3 u + 3 u
= 6 u
Fraction of N that is unshaded
= 1 -
15 =
45 15 of N = 6 u
45 of N = 4 x 6 u = 24 u
Fraction of the figure that is shaded if 20% of Triangle N is shaded
=
6 + 617 + 24 + 9 + 6 + 6 =
1262=
631 Answer(s):
631