The figure, not drawn to scale, is made up of 3 different triangles H, J and K. 20% of triangle H and 30% of triangle K is shaded. The shaded area of H is the same as the shaded area of K. What fraction of the figure is shaded if 25% of Triangle J is shaded?
Unshaded area of H |
Shaded area of H |
Unshaded area of K |
Shaded area of K |
4x3 |
1x3 |
7x1 |
3x1 |
12 u |
3 u |
7 u |
3 u |
20% =
20100 =
15 30% =
30100 =
310 25% =
25100 =
14The shaded area of H is the same as the shaded area of K.
Make the LCM of the shaded area of H and shaded area of K the same.
LCM of 1 and 3 = 3
14 of J is shaded
= Shaded area of H + Shaded area of K
= 3 u + 3 u
= 6 u
Fraction of J that is unshaded
= 1 -
14 =
34 14 of J = 6 u
34 of J = 3 x 6 u = 18 u
Fraction of the figure that is shaded if 25% of Triangle J is shaded
=
6 + 612 + 18 + 7 + 6 + 6=
1249 Answer(s):
1249