The figure, not drawn to scale, is made up of 3 different triangles M, N and P. 25% of triangle M and 35% of triangle P is shaded. The shaded area of M is the same as the shaded area of P. What fraction of the figure is shaded if 20% of Triangle N is shaded?
Unshaded area of M |
Shaded area of M |
Unshaded area of P |
Shaded area of P |
3x7 |
1x7 |
13x1 |
7x1 |
21 u |
7 u |
13 u |
7 u |
25% =
25100 =
14 35% =
35100 =
720 20% =
20100 =
15The shaded area of M is the same as the shaded area of P.
Make the LCM of the shaded area of M and shaded area of P the same.
LCM of 1 and 7 = 7
15 of N is shaded
= Shaded area of M + Shaded area of P
= 7 u + 7 u
= 14 u
Fraction of N that is unshaded
= 1 -
15 =
45 15 of N = 14 u
45 of N = 4 x 14 u = 56 u
Fraction of the figure that is shaded if 20% of Triangle N is shaded
=
14 + 1421 + 56 + 13 + 14 + 14 =
28118=
1459 Answer(s):
1459