The figure, not drawn to scale, is made up of 3 different triangles C, D and E. 25% of triangle C and 30% of triangle E is shaded. The shaded area of C is the same as the shaded area of E. What fraction of the figure is shaded if 20% of Triangle D is shaded?

Unshaded area of C	Shaded area of C	Unshaded area of E	Shaded area of E
3x3	1x3	7x1	3x1
9 u	3 u	7 u	3 u

25% = ²⁵₁₀₀ = ¹₄
30% = ³⁰₁₀₀ = ³₁₀
20% = ²⁰₁₀₀ = ¹₅
The shaded area of C is the same as the shaded area of E.

Make the LCM of the shaded area of C and shaded area of E the same.
LCM of 1 and 3 = 3

¹₅ of D is shaded
= Shaded area of C + Shaded area of E
= 3 u + 3 u
= 6 u

Fraction of D that is unshaded 
= 1 - ¹₅
= ⁴₅ 

¹₅ of D = 6 u
⁴₅ of D = 4 x 6 u = 24 u

Fraction of the figure that is shaded if 20% of Triangle D is shaded
= ^{6 + 6}_{9 + 24 + 7 + 6 + 6}
= ¹²₅₂
= ³₁₃

Answer(s): ³₁₃