At a factory, Nick could assemble 6 robots in a day while Julian could assemble 3 more robots than him in a day. If Julian was absent for 2 days, how many days would he need to assemble 22 more robots than Nick?
3 m
At a factory, Nick could assemble 6 robots in a day while Julian could assemble 3 more robots than him in a day. If Julian was absent for 2 days, how many days would he need to assemble 22 more robots than Nick?
Symbols
Enter the numerator and denominator
Enter value
2
1-minute grace period
When you click the Next button, you will be given 1-minute grace period to decide
whether to do the next question type.
The question will be marked as incorrect if you exceed 1 minute and leave the question page.
Click the Back button instead if you would like to return to the topic page.
Ischool Pte Ltd
Date:18 May 2024
Topic:
SPEED
Question Code:
P6.SP.JC.18011001
Student:
Class:
Level:
School:
At a factory, Nick could assemble 6 robots in a day while Julian could assemble 3 more robots than him in a day. If Julian was absent for 2 days, how many days would he need to assemble 22 more robots than Nick?
(3 m)
Ischool Pte Ltd
Date:
18 May 2024
Topic:
SPEED
Question Code:
P6.SP.JC.18011001
Student:
Class:
Level:
School:
At a factory, Nick could assemble 6 robots in a day while Julian could assemble 3 more robots than him in a day. If Julian was absent for 2 days, how many days would he need to assemble 22 more robots than Nick?
At a factory, Nick could assemble 6 robots in a day while Julian could assemble 3 more robots than him in a day. If Julian was absent for 2 days, how many days would he need to assemble 22 more robots than Nick?
Message
To help you learn well, you can save up to
5 questions per question types in the Notepad History for review.
The latest 5 questions willautomatically replace the earliest one.
If a question islocked, it will not be automatically deleted.
If 5 questions are locked, new questionscannot be saved.
To save new questions,unlock ordelete the existing questions in the
notepad history.
ISchool Pte Ltd
Date:18 May 2024
Topic:SPEED
Question Number:P6.SP.JC.18011001-A1
Student:
Class:
Level:
School:
Promo Code
Promo Code:
SELECT PLAN TYPE
Subscribe Today!
Oops! The free trial period has expired.
Enjoy the full features by subscribing to iSchool today.
