At a factory, Brandon could assemble 9 toy helicopters in a day while Julian could assemble 5 more toy helicopters than him in a day. If Julian was absent for 4 days, how many days would he need to assemble 18 more toy helicopters than Brandon?
3 m
At a factory, Brandon could assemble 9 toy helicopters in a day while Julian could assemble 5 more toy helicopters than him in a day. If Julian was absent for 4 days, how many days would he need to assemble 18 more toy helicopters than Brandon?
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Ischool Pte Ltd
Date:21 Jun 2024
Topic:
SPEED
Question Code:
P6.SP.JC.18011001
Student:
Class:
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At a factory, Brandon could assemble 9 toy helicopters in a day while Julian could assemble 5 more toy helicopters than him in a day. If Julian was absent for 4 days, how many days would he need to assemble 18 more toy helicopters than Brandon?
(3 m)
Ischool Pte Ltd
Date:
21 Jun 2024
Topic:
SPEED
Question Code:
P6.SP.JC.18011001
Student:
Class:
Level:
School:
At a factory, Brandon could assemble 9 toy helicopters in a day while Julian could assemble 5 more toy helicopters than him in a day. If Julian was absent for 4 days, how many days would he need to assemble 18 more toy helicopters than Brandon?
At a factory, Brandon could assemble 9 toy helicopters in a day while Julian could assemble 5 more toy helicopters than him in a day. If Julian was absent for 4 days, how many days would he need to assemble 18 more toy helicopters than Brandon?
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ISchool Pte Ltd
Date:21 Jun 2024
Topic:SPEED
Question Number:P6.SP.JC.18011001-A1
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