Christian has 2 containers. Container U and Container V are of different capacities. If Container U is filled by a tap at a rate of 4 litres per minute and Container V is filled by a tap at a rate of 6 litres per minute, when Container U is completely filled, 6 litres of water flowed out from Container V. If Container U is filled by a tap at a rate of 6 litres per minute and Container V is filled by a tap at a rate of 3 litres per minute, when Container U is completely filled, Container V is only half-filled. What is the capacity of Container V? Express your answer in litres.
|
Scenario 1 |
Scenario 2 |
Container type |
Container U |
Container V |
Container U |
Container V |
Volume of the container |
4 u |
6 u - 6 |
6 p |
3 p x 2 = 6 p |
Let 1 u be the time taken for Scenario 1.
Let 1 p be the time taken for Scenario 2.
4 u = 6 p --- (1)
6 u - 6 = 6 p
6 u = 6 p + 6 --- (2)
Make u the same.
(1) x 3
12 u = 18 p --- (3)
(2) x 2
12 u = 12 p + 12 --- (4)
(3) = (4)
18 p = 12 p + 12
18 p - 12 p = 12
6 p = 12
1 p = 12 ÷ 6 = 2
Volume of Container V
= 6 p
= 6 x 2
= 12 ℓ
Answer(s): 12 ℓ