Caleb has 2 containers. Container U and Container V are of different capacities. If Container U is filled by a tap at a rate of 3 litres per minute and Container V is filled by a tap at a rate of 5 litres per minute, when Container U is completely filled, 7 litres of water flowed out from Container V. If Container U is filled by a tap at a rate of 4 litres per minute and Container V is filled by a tap at a rate of 2 litres per minute, when Container U is completely filled, Container V is only one-third-filled. What is the capacity of Container V? Express your answer in litres.
|
Scenario 1 |
Scenario 2 |
Container type |
Container U |
Container V |
Container U |
Container V |
Volume of the container |
3 u |
5 u - 7 |
4 p |
2 p x 3 = 6 p |
Let 1 u be the time taken for Scenario 1.
Let 1 p be the time taken for Scenario 2.
3 u = 4 p --- (1)
5 u - 7 = 6 p
5 u = 6 p + 7 --- (2)
Make u the same.
(1) x 5
15 u = 20 p --- (3)
(2) x 3
15 u = 18 p + 21 --- (4)
(3) = (4)
20 p = 18 p + 21
20 p - 18 p = 21
2 p = 21
1 p = 21 ÷ 2 = 10.5
Volume of Container V
= 6 p
= 6 x 10.5
= 63 ℓ
Answer(s): 63 ℓ