Lucas has 2 containers. Container Y and Container Z are of different capacities. If Container Y is filled by a tap at a rate of 4 litres per minute and Container Z is filled by a tap at a rate of 7 litres per minute, when Container Y is completely filled, 8 litres of water flowed out from Container Z. If Container Y is filled by a tap at a rate of 6 litres per minute and Container Z is filled by a tap at a rate of 2 litres per minute, when Container Y is completely filled, Container Z is only one-quarter-filled. What is the capacity of Container Z? Express your answer in litres.
|
Scenario 1 |
Scenario 2 |
Container type |
Container Y |
Container Z |
Container Y |
Container Z |
Volume of the container |
4 u |
7 u - 8 |
6 p |
2 p x 4 = 8 p |
Let 1 u be the time taken for Scenario 1.
Let 1 p be the time taken for Scenario 2.
4 u = 6 p --- (1)
7 u - 8 = 8 p
7 u = 8 p + 8 --- (2)
Make u the same.
(1) x 7
28 u = 42 p --- (3)
(2) x 4
28 u = 32 p + 32 --- (4)
(3) = (4)
42 p = 32 p + 32
42 p - 32 p = 32
10 p = 32
1 p = 32 ÷ 10 = 3.2
Volume of Container Z
= 8 p
= 8 x 3.2
= 25.6 ℓ
Answer(s): 25.6 ℓ