Machine A takes 8 minutes to cut 160 pieces of lumbers. Machine B takes 17 minutes to cut 102 pieces of lumbers. Machine C takes 11 minutes to cut 198 pieces of lumber.
- Which is the faster combination, A and B or B and C? (Eg A, B)
- In 1 minute, how many more pieces of lumbers can be cut by the faster combination compared to the other combination?
(a)
Time taken by Machine A alone:
8 min → 160 pieces
1 min → 160 ÷ 8 = 20 pieces
Time taken by Machine B alone:
17 min → 102 pieces
1 min → 102 ÷ 17 = 6 pieces
Time taken by Machine C alone:
11 min → 102 pieces
1 min → 198 ÷ 11 = 18 pieces
Time taken by Machine A and Machine B together:
1 min → 20 + 6 = 26 pieces
Time taken by Machine B and Machine C together:
1 min → 6 + 18 = 24 pieces
Machine A and B are the faster combination.
(b)
Number of more pieces of lumbers that can be cut by the faster combination (Machine A and B) in 1 minute
= 26 - 24
= 2
Answer(s): (a) A, B or B, A; (b) 2