Machine A takes 6 minutes to cut 60 pieces of lumbers. Machine B takes 16 minutes to cut 160 pieces of lumbers. Machine C takes 8 minutes to cut 96 pieces of lumber.
- Which is the faster combination, A and B or B and C? (Eg A, B)
- In 1 minute, how many more pieces of lumbers can be cut by the faster combination compared to the other combination?
(a)
Time taken by Machine A alone:
6 min → 60 pieces
1 min → 60 ÷ 6 = 10 pieces
Time taken by Machine B alone:
16 min → 160 pieces
1 min → 160 ÷ 16 = 10 pieces
Time taken by Machine C alone:
8 min → 160 pieces
1 min → 96 ÷ 8 = 12 pieces
Time taken by Machine A and Machine B together:
1 min → 10 + 10 = 20 pieces
Time taken by Machine B and Machine C together:
1 min → 10 + 12 = 22 pieces
Machine B and C are the faster combination.
(b)
Number of more pieces of lumbers that can be cut by the faster combination (Machine B and C) in 1 minute
= 22 - 20
= 2
Answer(s): (a) B, C or C, B; (b) 2