Machine Y takes 5 minutes to cut 55 pieces of lumbers. Machine Z takes 10 minutes to cut 60 pieces of lumbers. Machine A takes 12 minutes to cut 180 pieces of lumber.
- Which is the faster combination, Y and Z or Z and A? (Eg A, B)
- In 1 minute, how many more pieces of lumbers can be cut by the faster combination compared to the other combination?
(a)
Time taken by Machine Y alone:
5 min → 55 pieces
1 min → 55 ÷ 5 = 11 pieces
Time taken by Machine Z alone:
10 min → 60 pieces
1 min → 60 ÷ 10 = 6 pieces
Time taken by Machine A alone:
12 min → 60 pieces
1 min → 180 ÷ 12 = 15 pieces
Time taken by Machine Y and Machine Z together:
1 min → 11 + 6 = 17 pieces
Time taken by Machine Z and Machine A together:
1 min → 6 + 15 = 21 pieces
Machine Z and A are the faster combination.
(b)
Number of more pieces of lumbers that can be cut by the faster combination (Machine Z and A) in 1 minute
= 21 - 17
= 4
Answer(s): (a) Z, A or A, Z; (b) 4