Machine A takes 8 minutes to cut 128 pieces of lumbers. Machine B takes 18 minutes to cut 198 pieces of lumbers. Machine C takes 12 minutes to cut 144 pieces of lumber.
- Which is the faster combination, A and B or B and C? (Eg A, B)
- In 1 minute, how many more pieces of lumbers can be cut by the faster combination compared to the other combination?
(a)
Time taken by Machine A alone:
8 min → 128 pieces
1 min → 128 ÷ 8 = 16 pieces
Time taken by Machine B alone:
18 min → 198 pieces
1 min → 198 ÷ 18 = 11 pieces
Time taken by Machine C alone:
12 min → 198 pieces
1 min → 144 ÷ 12 = 12 pieces
Time taken by Machine A and Machine B together:
1 min → 16 + 11 = 27 pieces
Time taken by Machine B and Machine C together:
1 min → 11 + 12 = 23 pieces
Machine A and B are the faster combination.
(b)
Number of more pieces of lumbers that can be cut by the faster combination (Machine A and B) in 1 minute
= 27 - 23
= 4
Answer(s): (a) A, B or B, A; (b) 4