Machine A takes 9 minutes to cut 162 pieces of lumbers. Machine B takes 14 minutes to cut 140 pieces of lumbers. Machine C takes 8 minutes to cut 96 pieces of lumber.
- Which is the faster combination, A and B or B and C? (Eg A, B)
- In 1 minute, how many more pieces of lumbers can be cut by the faster combination compared to the other combination?
(a)
Time taken by Machine A alone:
9 min → 162 pieces
1 min → 162 ÷ 9 = 18 pieces
Time taken by Machine B alone:
14 min → 140 pieces
1 min → 140 ÷ 14 = 10 pieces
Time taken by Machine C alone:
8 min → 140 pieces
1 min → 96 ÷ 8 = 12 pieces
Time taken by Machine A and Machine B together:
1 min → 18 + 10 = 28 pieces
Time taken by Machine B and Machine C together:
1 min → 10 + 12 = 22 pieces
Machine A and B are the faster combination.
(b)
Number of more pieces of lumbers that can be cut by the faster combination (Machine A and B) in 1 minute
= 28 - 22
= 6
Answer(s): (a) A, B or B, A; (b) 6