At 8 a.m., Justin left Hotel Y in his car and travelled towards Hotel Z at 78 km/h. At the same time, Howard left Hotel Y in his car and travelled in the opposite direction towards Hotel A. When Howard reached Hotel A at 10.30 a.m., Justin was 15 km away from Hotel Z.
- What was the distance from Hotel Y to Hotel Z?
- If the distance between Hotel Z and Hotel A was 410 km, what was Howard's speed?
(a)
From 8 a.m. to 10.30. am = 2 h 30 min
60 min = 1 h
1 min =
160 h
30 min =
3060 =
12 h
2 h 30 min = 2
12 h
Distance from Hotel Y to Hotel Z
= 78 x 2
12 + 15
= 78 x
52 + 15
= 195 + 15
= 210 km
(b)
Distance travelled by Howard
= 410 - 210
= 200 km
Howard's speed
= 200 ÷ 2
12 = 200 ÷
52 = 200 x
25 = 80 km/h
Answer(s): (a) 210 km; (b) 80 km/h