At 9 a.m., Pierre left Hotel U in his car and travelled towards Hotel V at 80 km/h. At the same time, Gabriel left Hotel U in his car and travelled in the opposite direction towards Hotel W. When Gabriel reached Hotel W at 11.30 a.m., Pierre was 10 km away from Hotel V.
- What was the distance from Hotel U to Hotel V?
- If the distance between Hotel V and Hotel W was 440 km, what was Gabriel's speed?
(a)
From 9 a.m. to 11.30. am = 2 h 30 min
60 min = 1 h
1 min =
160 h
30 min =
3060 =
12 h
2 h 30 min = 2
12 h
Distance from Hotel U to Hotel V
= 80 x 2
12 + 10
= 80 x
52 + 10
= 200 + 10
= 210 km
(b)
Distance travelled by Gabriel
= 440 - 210
= 230 km
Gabriel's speed
= 230 ÷ 2
12 = 230 ÷
52 = 230 x
25 = 92 km/h
Answer(s): (a) 210 km; (b) 92 km/h