At 7 a.m., Bryan left Hotel T in his car and travelled towards Hotel U at 84 km/h. At the same time, Flynn left Hotel T in his car and travelled in the opposite direction towards Hotel V. When Flynn reached Hotel V at 9.30 a.m., Bryan was 10 km away from Hotel U.
- What was the distance from Hotel T to Hotel U?
- If the distance between Hotel U and Hotel V was 410 km, what was Flynn's speed?
(a)
From 7 a.m. to 9.30. am = 2 h 30 min
60 min = 1 h
1 min =
160 h
30 min =
3060 =
12 h
2 h 30 min = 2
12 h
Distance from Hotel T to Hotel U
= 84 x 2
12 + 10
= 84 x
52 + 10
= 210 + 10
= 220 km
(b)
Distance travelled by Flynn
= 410 - 220
= 190 km
Flynn's speed
= 190 ÷ 2
12 = 190 ÷
52 = 190 x
25 = 76 km/h
Answer(s): (a) 220 km; (b) 76 km/h