At 6 a.m., Brandon left Hotel T in his car and travelled towards Hotel U at 74 km/h. At the same time, Gabriel left Hotel T in his car and travelled in the opposite direction towards Hotel V. When Gabriel reached Hotel V at 8.30 a.m., Brandon was 10 km away from Hotel U.
- What was the distance from Hotel T to Hotel U?
- If the distance between Hotel U and Hotel V was 420 km, what was Gabriel's speed?
(a)
From 6 a.m. to 8.30. am = 2 h 30 min
60 min = 1 h
1 min =
160 h
30 min =
3060 =
12 h
2 h 30 min = 2
12 h
Distance from Hotel T to Hotel U
= 74 x 2
12 + 10
= 74 x
52 + 10
= 185 + 10
= 195 km
(b)
Distance travelled by Gabriel
= 420 - 195
= 225 km
Gabriel's speed
= 225 ÷ 2
12 = 225 ÷
52 = 225 x
25 = 90 km/h
Answer(s): (a) 195 km; (b) 90 km/h