At 9 a.m., Cole left Hotel V in his car and travelled towards Hotel W at 96 km/h. At the same time, Luke left Hotel V in his car and travelled in the opposite direction towards Hotel X. When Luke reached Hotel X at 11.50 a.m., Cole was 15 km away from Hotel W.
- What was the distance from Hotel V to Hotel W?
- If the distance between Hotel W and Hotel X was 440 km, what was Luke's speed?
(a)
From 9 a.m. to 11.50. am = 2 h 50 min
60 min = 1 h
1 min =
160 h
50 min =
5060 =
56 h
2 h 50 min = 2
56 h
Distance from Hotel V to Hotel W
= 96 x 2
56 + 15
= 96 x
176 + 15
= 272 + 15
= 287 km
(b)
Distance travelled by Luke
= 440 - 287
= 153 km
Luke's speed
= 153 ÷ 2
56 = 153 ÷
176 = 153 x
617 = 54 km/h
Answer(s): (a) 287 km; (b) 54 km/h