At 6 a.m., Andy left Hotel E in his car and travelled towards Hotel F at 98 km/h. At the same time, Cody left Hotel E in his car and travelled in the opposite direction towards Hotel G. When Cody reached Hotel G at 8.30 a.m., Andy was 10 km away from Hotel F.
- What was the distance from Hotel E to Hotel F?
- If the distance between Hotel F and Hotel G was 410 km, what was Cody's speed?
(a)
From 6 a.m. to 8.30. am = 2 h 30 min
60 min = 1 h
1 min =
160 h
30 min =
3060 =
12 h
2 h 30 min = 2
12 h
Distance from Hotel E to Hotel F
= 98 x 2
12 + 10
= 98 x
52 + 10
= 245 + 10
= 255 km
(b)
Distance travelled by Cody
= 410 - 255
= 155 km
Cody's speed
= 155 ÷ 2
12 = 155 ÷
52 = 155 x
25 = 62 km/h
Answer(s): (a) 255 km; (b) 62 km/h