At 6 a.m., Ethan left Hotel U in his car and travelled towards Hotel V at 75 km/h. At the same time, Neave left Hotel U in his car and travelled in the opposite direction towards Hotel W. When Neave reached Hotel W at 9.20 a.m., Ethan was 10 km away from Hotel V.
- What was the distance from Hotel U to Hotel V?
- If the distance between Hotel V and Hotel W was 430 km, what was Neave's speed?
(a)
From 6 a.m. to 9.20. am = 3 h 20 min
60 min = 1 h
1 min =
160 h
20 min =
2060 =
13 h
3 h 20 min = 3
13 h
Distance from Hotel U to Hotel V
= 75 x 3
13 + 10
= 75 x
103 + 10
= 250 + 10
= 260 km
(b)
Distance travelled by Neave
= 430 - 260
= 170 km
Neave's speed
= 170 ÷ 3
13 = 170 ÷
103 = 170 x
310 = 51 km/h
Answer(s): (a) 260 km; (b) 51 km/h