At 6 a.m., Jack left Hotel U in his car and travelled towards Hotel V at 72 km/h. At the same time, Charlie left Hotel U in his car and travelled in the opposite direction towards Hotel W. When Charlie reached Hotel W at 9.15 a.m., Jack was 11 km away from Hotel V.
- What was the distance from Hotel U to Hotel V?
- If the distance between Hotel V and Hotel W was 440 km, what was Charlie's speed?
(a)
From 6 a.m. to 9.15. am = 3 h 15 min
60 min = 1 h
1 min =
160 h
15 min =
1560 =
14 h
3 h 15 min = 3
14 h
Distance from Hotel U to Hotel V
= 72 x 3
14 + 11
= 72 x
134 + 11
= 234 + 11
= 245 km
(b)
Distance travelled by Charlie
= 440 - 245
= 195 km
Charlie's speed
= 195 ÷ 3
14 = 195 ÷
134 = 195 x
413 = 60 km/h
Answer(s): (a) 245 km; (b) 60 km/h