At 5 a.m., Charlie left Hotel R in his car and travelled towards Hotel S at 96 km/h. At the same time, Caden left Hotel R in his car and travelled in the opposite direction towards Hotel T. When Caden reached Hotel T at 7.10 a.m., Charlie was 16 km away from Hotel S.
- What was the distance from Hotel R to Hotel S?
- If the distance between Hotel S and Hotel T was 380 km, what was Caden's speed?
(a)
From 5 a.m. to 7.10. am = 2 h 10 min
60 min = 1 h
1 min =
160 h
10 min =
1060 =
16 h
2 h 10 min = 2
16 h
Distance from Hotel R to Hotel S
= 96 x 2
16 + 16
= 96 x
136 + 16
= 208 + 16
= 224 km
(b)
Distance travelled by Caden
= 380 - 224
= 156 km
Caden's speed
= 156 ÷ 2
16 = 156 ÷
136 = 156 x
613 = 72 km/h
Answer(s): (a) 224 km; (b) 72 km/h