At 9 a.m., Asher left Hotel Y in his car and travelled towards Hotel Z at 81 km/h. At the same time, Jack left Hotel Y in his car and travelled in the opposite direction towards Hotel A. When Jack reached Hotel A at 11.40 a.m., Asher was 10 km away from Hotel Z.
- What was the distance from Hotel Y to Hotel Z?
- If the distance between Hotel Z and Hotel A was 410 km, what was Jack's speed?
(a)
From 9 a.m. to 11.40. am = 2 h 40 min
60 min = 1 h
1 min =
160 h
40 min =
4060 =
23 h
2 h 40 min = 2
23 h
Distance from Hotel Y to Hotel Z
= 81 x 2
23 + 10
= 81 x
83 + 10
= 216 + 10
= 226 km
(b)
Distance travelled by Jack
= 410 - 226
= 184 km
Jack's speed
= 184 ÷ 2
23 = 184 ÷
83 = 184 x
38 = 69 km/h
Answer(s): (a) 226 km; (b) 69 km/h