At 5 a.m., Luke left Hotel C in his car and travelled towards Hotel D at 87 km/h. At the same time, Ken left Hotel C in his car and travelled in the opposite direction towards Hotel E. When Ken reached Hotel E at 7.20 a.m., Luke was 14 km away from Hotel D.
- What was the distance from Hotel C to Hotel D?
- If the distance between Hotel D and Hotel E was 420 km, what was Ken's speed?
(a)
From 5 a.m. to 7.20. am = 2 h 20 min
60 min = 1 h
1 min =
160 h
20 min =
2060 =
13 h
2 h 20 min = 2
13 h
Distance from Hotel C to Hotel D
= 87 x 2
13 + 14
= 87 x
73 + 14
= 203 + 14
= 217 km
(b)
Distance travelled by Ken
= 420 - 217
= 203 km
Ken's speed
= 203 ÷ 2
13 = 203 ÷
73 = 203 x
37 = 87 km/h
Answer(s): (a) 217 km; (b) 87 km/h