At 6 a.m., Luis left Hotel D in his car and travelled towards Hotel E at 74 km/h. At the same time, Archie left Hotel D in his car and travelled in the opposite direction towards Hotel F. When Archie reached Hotel F at 8.30 a.m., Luis was 20 km away from Hotel E.
- What was the distance from Hotel D to Hotel E?
- If the distance between Hotel E and Hotel F was 410 km, what was Archie's speed?
(a)
From 6 a.m. to 8.30. am = 2 h 30 min
60 min = 1 h
1 min =
160 h
30 min =
3060 =
12 h
2 h 30 min = 2
12 h
Distance from Hotel D to Hotel E
= 74 x 2
12 + 20
= 74 x
52 + 20
= 185 + 20
= 205 km
(b)
Distance travelled by Archie
= 410 - 205
= 205 km
Archie's speed
= 205 ÷ 2
12 = 205 ÷
52 = 205 x
25 = 82 km/h
Answer(s): (a) 205 km; (b) 82 km/h