At 9 a.m., Fred left Hotel R in his car and travelled towards Hotel S at 92 km/h. At the same time, Bobby left Hotel R in his car and travelled in the opposite direction towards Hotel T. When Bobby reached Hotel T at 11.45 a.m., Fred was 11 km away from Hotel S.
- What was the distance from Hotel R to Hotel S?
- If the distance between Hotel S and Hotel T was 440 km, what was Bobby's speed?
(a)
From 9 a.m. to 11.45. am = 2 h 45 min
60 min = 1 h
1 min =
160 h
45 min =
4560 =
34 h
2 h 45 min = 2
34 h
Distance from Hotel R to Hotel S
= 92 x 2
34 + 11
= 92 x
114 + 11
= 253 + 11
= 264 km
(b)
Distance travelled by Bobby
= 440 - 264
= 176 km
Bobby's speed
= 176 ÷ 2
34 = 176 ÷
114 = 176 x
411 = 64 km/h
Answer(s): (a) 264 km; (b) 64 km/h