At 6 a.m., Lee left Hotel Z in his car and travelled towards Hotel A at 86 km/h. At the same time, Luke left Hotel Z in his car and travelled in the opposite direction towards Hotel B. When Luke reached Hotel B at 8.30 a.m., Lee was 20 km away from Hotel A.
- What was the distance from Hotel Z to Hotel A?
- If the distance between Hotel A and Hotel B was 430 km, what was Luke's speed?
(a)
From 6 a.m. to 8.30. am = 2 h 30 min
60 min = 1 h
1 min =
160 h
30 min =
3060 =
12 h
2 h 30 min = 2
12 h
Distance from Hotel Z to Hotel A
= 86 x 2
12 + 20
= 86 x
52 + 20
= 215 + 20
= 235 km
(b)
Distance travelled by Luke
= 430 - 235
= 195 km
Luke's speed
= 195 ÷ 2
12 = 195 ÷
52 = 195 x
25 = 78 km/h
Answer(s): (a) 235 km; (b) 78 km/h