At 6 a.m., Brandon left Hotel Y in his car and travelled towards Hotel Z at 78 km/h. At the same time, Billy left Hotel Y in his car and travelled in the opposite direction towards Hotel A. When Billy reached Hotel A at 8.50 a.m., Brandon was 16 km away from Hotel Z.
- What was the distance from Hotel Y to Hotel Z?
- If the distance between Hotel Z and Hotel A was 390 km, what was Billy's speed?
(a)
From 6 a.m. to 8.50. am = 2 h 50 min
60 min = 1 h
1 min =
160 h
50 min =
5060 =
56 h
2 h 50 min = 2
56 h
Distance from Hotel Y to Hotel Z
= 78 x 2
56 + 16
= 78 x
176 + 16
= 221 + 16
= 237 km
(b)
Distance travelled by Billy
= 390 - 237
= 153 km
Billy's speed
= 153 ÷ 2
56 = 153 ÷
176 = 153 x
617 = 54 km/h
Answer(s): (a) 237 km; (b) 54 km/h