At 6 a.m., Rael left Hotel R in his car and travelled towards Hotel S at 96 km/h. At the same time, Cody left Hotel R in his car and travelled in the opposite direction towards Hotel T. When Cody reached Hotel T at 8.15 a.m., Rael was 12 km away from Hotel S.
- What was the distance from Hotel R to Hotel S?
- If the distance between Hotel S and Hotel T was 390 km, what was Cody's speed?
(a)
From 6 a.m. to 8.15. am = 2 h 15 min
60 min = 1 h
1 min =
160 h
15 min =
1560 =
14 h
2 h 15 min = 2
14 h
Distance from Hotel R to Hotel S
= 96 x 2
14 + 12
= 96 x
94 + 12
= 216 + 12
= 228 km
(b)
Distance travelled by Cody
= 390 - 228
= 162 km
Cody's speed
= 162 ÷ 2
14 = 162 ÷
94 = 162 x
49 = 72 km/h
Answer(s): (a) 228 km; (b) 72 km/h