At 9 a.m., Wesley left Hotel P in his car and travelled towards Hotel Q at 94 km/h. At the same time, Sean left Hotel P in his car and travelled in the opposite direction towards Hotel R. When Sean reached Hotel R at 11.30 a.m., Wesley was 20 km away from Hotel Q.
- What was the distance from Hotel P to Hotel Q?
- If the distance between Hotel Q and Hotel R was 420 km, what was Sean's speed?
(a)
From 9 a.m. to 11.30. am = 2 h 30 min
60 min = 1 h
1 min =
160 h
30 min =
3060 =
12 h
2 h 30 min = 2
12 h
Distance from Hotel P to Hotel Q
= 94 x 2
12 + 20
= 94 x
52 + 20
= 235 + 20
= 255 km
(b)
Distance travelled by Sean
= 420 - 255
= 165 km
Sean's speed
= 165 ÷ 2
12 = 165 ÷
52 = 165 x
25 = 66 km/h
Answer(s): (a) 255 km; (b) 66 km/h