At 6 a.m., Reggie left Hotel R in his car and travelled towards Hotel S at 76 km/h. At the same time, Fred left Hotel R in his car and travelled in the opposite direction towards Hotel T. When Fred reached Hotel T at 8.30 a.m., Reggie was 20 km away from Hotel S.
- What was the distance from Hotel R to Hotel S?
- If the distance between Hotel S and Hotel T was 410 km, what was Fred's speed?
(a)
From 6 a.m. to 8.30. am = 2 h 30 min
60 min = 1 h
1 min =
160 h
30 min =
3060 =
12 h
2 h 30 min = 2
12 h
Distance from Hotel R to Hotel S
= 76 x 2
12 + 20
= 76 x
52 + 20
= 190 + 20
= 210 km
(b)
Distance travelled by Fred
= 410 - 210
= 200 km
Fred's speed
= 200 ÷ 2
12 = 200 ÷
52 = 200 x
25 = 80 km/h
Answer(s): (a) 210 km; (b) 80 km/h