At 8 a.m., Justin left Hotel V in his car and travelled towards Hotel W at 78 km/h. At the same time, Lee left Hotel V in his car and travelled in the opposite direction towards Hotel X. When Lee reached Hotel X at 10.40 a.m., Justin was 10 km away from Hotel W.
- What was the distance from Hotel V to Hotel W?
- If the distance between Hotel W and Hotel X was 450 km, what was Lee's speed?
(a)
From 8 a.m. to 10.40. am = 2 h 40 min
60 min = 1 h
1 min =
160 h
40 min =
4060 =
23 h
2 h 40 min = 2
23 h
Distance from Hotel V to Hotel W
= 78 x 2
23 + 10
= 78 x
83 + 10
= 208 + 10
= 218 km
(b)
Distance travelled by Lee
= 450 - 218
= 232 km
Lee's speed
= 232 ÷ 2
23 = 232 ÷
83 = 232 x
38 = 87 km/h
Answer(s): (a) 218 km; (b) 87 km/h