At 8 a.m., Fabian left Hotel A in his car and travelled towards Hotel B at 86 km/h. At the same time, Brandon left Hotel A in his car and travelled in the opposite direction towards Hotel C. When Brandon reached Hotel C at 10.30 a.m., Fabian was 15 km away from Hotel B.
- What was the distance from Hotel A to Hotel B?
- If the distance between Hotel B and Hotel C was 430 km, what was Brandon's speed?
(a)
From 8 a.m. to 10.30. am = 2 h 30 min
60 min = 1 h
1 min =
160 h
30 min =
3060 =
12 h
2 h 30 min = 2
12 h
Distance from Hotel A to Hotel B
= 86 x 2
12 + 15
= 86 x
52 + 15
= 215 + 15
= 230 km
(b)
Distance travelled by Brandon
= 430 - 230
= 200 km
Brandon's speed
= 200 ÷ 2
12 = 200 ÷
52 = 200 x
25 = 80 km/h
Answer(s): (a) 230 km; (b) 80 km/h