At 8 a.m., Fabian left Hotel S in his car and travelled towards Hotel T at 72 km/h. At the same time, Cody left Hotel S in his car and travelled in the opposite direction towards Hotel U. When Cody reached Hotel U at 10.15 a.m., Fabian was 13 km away from Hotel T.
- What was the distance from Hotel S to Hotel T?
- If the distance between Hotel T and Hotel U was 400 km, what was Cody's speed?
(a)
From 8 a.m. to 10.15. am = 2 h 15 min
60 min = 1 h
1 min =
160 h
15 min =
1560 =
14 h
2 h 15 min = 2
14 h
Distance from Hotel S to Hotel T
= 72 x 2
14 + 13
= 72 x
94 + 13
= 162 + 13
= 175 km
(b)
Distance travelled by Cody
= 400 - 175
= 225 km
Cody's speed
= 225 ÷ 2
14 = 225 ÷
94 = 225 x
49 = 100 km/h
Answer(s): (a) 175 km; (b) 100 km/h