At 8 a.m., Ethan left Hotel A in his car and travelled towards Hotel B at 100 km/h. At the same time, Sean left Hotel A in his car and travelled in the opposite direction towards Hotel C. When Sean reached Hotel C at 10.30 a.m., Ethan was 20 km away from Hotel B.
- What was the distance from Hotel A to Hotel B?
- If the distance between Hotel B and Hotel C was 450 km, what was Sean's speed?
(a)
From 8 a.m. to 10.30. am = 2 h 30 min
60 min = 1 h
1 min =
160 h
30 min =
3060 =
12 h
2 h 30 min = 2
12 h
Distance from Hotel A to Hotel B
= 100 x 2
12 + 20
= 100 x
52 + 20
= 250 + 20
= 270 km
(b)
Distance travelled by Sean
= 450 - 270
= 180 km
Sean's speed
= 180 ÷ 2
12 = 180 ÷
52 = 180 x
25 = 72 km/h
Answer(s): (a) 270 km; (b) 72 km/h