At 5 a.m., Mark left Hotel A in his car and travelled towards Hotel B at 93 km/h. At the same time, Seth left Hotel A in his car and travelled in the opposite direction towards Hotel C. When Seth reached Hotel C at 7.20 a.m., Mark was 17 km away from Hotel B.
- What was the distance from Hotel A to Hotel B?
- If the distance between Hotel B and Hotel C was 430 km, what was Seth's speed?
(a)
From 5 a.m. to 7.20. am = 2 h 20 min
60 min = 1 h
1 min =
160 h
20 min =
2060 =
13 h
2 h 20 min = 2
13 h
Distance from Hotel A to Hotel B
= 93 x 2
13 + 17
= 93 x
73 + 17
= 217 + 17
= 234 km
(b)
Distance travelled by Seth
= 430 - 234
= 196 km
Seth's speed
= 196 ÷ 2
13 = 196 ÷
73 = 196 x
37 = 84 km/h
Answer(s): (a) 234 km; (b) 84 km/h