At 9 a.m., Fred left Hotel Q in his car and travelled towards Hotel R at 74 km/h. At the same time, Caden left Hotel Q in his car and travelled in the opposite direction towards Hotel S. When Caden reached Hotel S at 11.30 a.m., Fred was 15 km away from Hotel R.
- What was the distance from Hotel Q to Hotel R?
- If the distance between Hotel R and Hotel S was 420 km, what was Caden's speed?
(a)
From 9 a.m. to 11.30. am = 2 h 30 min
60 min = 1 h
1 min =
160 h
30 min =
3060 =
12 h
2 h 30 min = 2
12 h
Distance from Hotel Q to Hotel R
= 74 x 2
12 + 15
= 74 x
52 + 15
= 185 + 15
= 200 km
(b)
Distance travelled by Caden
= 420 - 200
= 220 km
Caden's speed
= 220 ÷ 2
12 = 220 ÷
52 = 220 x
25 = 88 km/h
Answer(s): (a) 200 km; (b) 88 km/h