At 5 a.m., Henry left Hotel C in his car and travelled towards Hotel D at 80 km/h. At the same time, Ken left Hotel C in his car and travelled in the opposite direction towards Hotel E. When Ken reached Hotel E at 7.45 a.m., Henry was 14 km away from Hotel D.
- What was the distance from Hotel C to Hotel D?
- If the distance between Hotel D and Hotel E was 410 km, what was Ken's speed?
(a)
From 5 a.m. to 7.45. am = 2 h 45 min
60 min = 1 h
1 min =
160 h
45 min =
4560 =
34 h
2 h 45 min = 2
34 h
Distance from Hotel C to Hotel D
= 80 x 2
34 + 14
= 80 x
114 + 14
= 220 + 14
= 234 km
(b)
Distance travelled by Ken
= 410 - 234
= 176 km
Ken's speed
= 176 ÷ 2
34 = 176 ÷
114 = 176 x
411 = 64 km/h
Answer(s): (a) 234 km; (b) 64 km/h