At 6 a.m., Oscar left Hotel W in his car and travelled towards Hotel X at 88 km/h. At the same time, Howard left Hotel W in his car and travelled in the opposite direction towards Hotel Y. When Howard reached Hotel Y at 8.30 a.m., Oscar was 15 km away from Hotel X.
- What was the distance from Hotel W to Hotel X?
- If the distance between Hotel X and Hotel Y was 450 km, what was Howard's speed?
(a)
From 6 a.m. to 8.30. am = 2 h 30 min
60 min = 1 h
1 min =
160 h
30 min =
3060 =
12 h
2 h 30 min = 2
12 h
Distance from Hotel W to Hotel X
= 88 x 2
12 + 15
= 88 x
52 + 15
= 220 + 15
= 235 km
(b)
Distance travelled by Howard
= 450 - 235
= 215 km
Howard's speed
= 215 ÷ 2
12 = 215 ÷
52 = 215 x
25 = 86 km/h
Answer(s): (a) 235 km; (b) 86 km/h