At 8 a.m., Andy left Hotel Y in his car and travelled towards Hotel Z at 93 km/h. At the same time, Reggie left Hotel Y in his car and travelled in the opposite direction towards Hotel A. When Reggie reached Hotel A at 10.40 a.m., Andy was 14 km away from Hotel Z.
- What was the distance from Hotel Y to Hotel Z?
- If the distance between Hotel Z and Hotel A was 430 km, what was Reggie's speed?
(a)
From 8 a.m. to 10.40. am = 2 h 40 min
60 min = 1 h
1 min =
160 h
40 min =
4060 =
23 h
2 h 40 min = 2
23 h
Distance from Hotel Y to Hotel Z
= 93 x 2
23 + 14
= 93 x
83 + 14
= 248 + 14
= 262 km
(b)
Distance travelled by Reggie
= 430 - 262
= 168 km
Reggie's speed
= 168 ÷ 2
23 = 168 ÷
83 = 168 x
38 = 63 km/h
Answer(s): (a) 262 km; (b) 63 km/h