At 9 a.m., Reggie left Hotel Z in his car and travelled towards Hotel A at 80 km/h. At the same time, Bobby left Hotel Z in his car and travelled in the opposite direction towards Hotel B. When Bobby reached Hotel B at 11.30 a.m., Reggie was 15 km away from Hotel A.
- What was the distance from Hotel Z to Hotel A?
- If the distance between Hotel A and Hotel B was 420 km, what was Bobby's speed?
(a)
From 9 a.m. to 11.30. am = 2 h 30 min
60 min = 1 h
1 min =
160 h
30 min =
3060 =
12 h
2 h 30 min = 2
12 h
Distance from Hotel Z to Hotel A
= 80 x 2
12 + 15
= 80 x
52 + 15
= 200 + 15
= 215 km
(b)
Distance travelled by Bobby
= 420 - 215
= 205 km
Bobby's speed
= 205 ÷ 2
12 = 205 ÷
52 = 205 x
25 = 82 km/h
Answer(s): (a) 215 km; (b) 82 km/h