At 5 a.m., Pierre left Hotel S in his car and travelled towards Hotel T at 87 km/h. At the same time, Owen left Hotel S in his car and travelled in the opposite direction towards Hotel U. When Owen reached Hotel U at 7.40 a.m., Pierre was 16 km away from Hotel T.
- What was the distance from Hotel S to Hotel T?
- If the distance between Hotel T and Hotel U was 400 km, what was Owen's speed?
(a)
From 5 a.m. to 7.40. am = 2 h 40 min
60 min = 1 h
1 min =
160 h
40 min =
4060 =
23 h
2 h 40 min = 2
23 h
Distance from Hotel S to Hotel T
= 87 x 2
23 + 16
= 87 x
83 + 16
= 232 + 16
= 248 km
(b)
Distance travelled by Owen
= 400 - 248
= 152 km
Owen's speed
= 152 ÷ 2
23 = 152 ÷
83 = 152 x
38 = 57 km/h
Answer(s): (a) 248 km; (b) 57 km/h