At 8 a.m., Brandon left Hotel D in his car and travelled towards Hotel E at 94 km/h. At the same time, Cole left Hotel D in his car and travelled in the opposite direction towards Hotel F. When Cole reached Hotel F at 10.30 a.m., Brandon was 10 km away from Hotel E.
- What was the distance from Hotel D to Hotel E?
- If the distance between Hotel E and Hotel F was 440 km, what was Cole's speed?
(a)
From 8 a.m. to 10.30. am = 2 h 30 min
60 min = 1 h
1 min =
160 h
30 min =
3060 =
12 h
2 h 30 min = 2
12 h
Distance from Hotel D to Hotel E
= 94 x 2
12 + 10
= 94 x
52 + 10
= 235 + 10
= 245 km
(b)
Distance travelled by Cole
= 440 - 245
= 195 km
Cole's speed
= 195 ÷ 2
12 = 195 ÷
52 = 195 x
25 = 78 km/h
Answer(s): (a) 245 km; (b) 78 km/h